5n^2+37n+42=0

Solution for 5n^2+37n+42=0 equation:

5n^2+37n+42=0

a = 5; b = 37; c = +42;
Δ = b2-4ac
Δ = 372-4·5·42
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-23}{2*5}=\frac{-60}{10}
=-6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+23}{2*5}=\frac{-14}{10}
=-1+2/5
$